If xy + ey = e, find the value of y" at the point where x = 0.

slaggingV 2021-09-14 Answered
If xy + ey = e, find the value of y" at the point where x = 0.
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

Demi-Leigh Barrera
Answered 2021-09-15 Author has 97 answers

0+ey=e plug in x=0 to the original equation this would then mean that y=1 where x=0 making the point be (0,1)
xy+y1+eyy=0 use implicit differentiation in terms of x to get this equation
0+1+e*y'=0 plug in 0 for X and 1 for Y and solve as far as you can.
y'=-1/e solve the previous equation for y'
(xy+y1+y)+(eyy+yeyy)=0 use implicit differentiation again with respect to x. Hint: You need to use the product rule to get this equation.
0+1e+1e+ey+1e×(e)(1e)=0 plug in the values you got before where x=0, y=1, and y=1e
2e+ey+1e=0 simplify the equation to get the final result.
Resut:
y=1e2

Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more