The multiplication of the expression (8x-3)(2x-4)

Ernstfalld 2021-09-21 Answered
The multiplication of the expression \(\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}\)

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Expert Answer

Neelam Wainwright
Answered 2021-09-22 Author has 6806 answers

Step 1
Concept used:
The multiplication of the expression \(\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}\) is calculated as,
\(\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}={8}{x}{\left({2}{x}-{4}\right)}-{3}{\left({2}{x}-{4}\right)}\)
\(\displaystyle={\left({8}{x}\right)}\cdot{\left({2}{x}\right)}+{\left({8}{x}\right)}\cdot{\left(-{4}\right)}+{\left(-{3}\right)}\cdot{\left({2}{x}\right)}+{\left(-{3}\right)}\cdot{\left(-{4}\right)}\)
\(\displaystyle={16}{x}^{{{2}}}-{32}{x}-{6}{x}+{12}\)
\(\displaystyle={16}{x}^{{{2}}}-{38}{x}+{12}\)
Thus, the multiplication of the expression \(\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}\) is \(16x^{2}-38x+12\)

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