# The multiplication of the expression (8x-3)(2x-4)

The multiplication of the expression $$\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}$$

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Neelam Wainwright

Step 1
Concept used:
The multiplication of the expression $$\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}$$ is calculated as,
$$\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}={8}{x}{\left({2}{x}-{4}\right)}-{3}{\left({2}{x}-{4}\right)}$$
$$\displaystyle={\left({8}{x}\right)}\cdot{\left({2}{x}\right)}+{\left({8}{x}\right)}\cdot{\left(-{4}\right)}+{\left(-{3}\right)}\cdot{\left({2}{x}\right)}+{\left(-{3}\right)}\cdot{\left(-{4}\right)}$$
$$\displaystyle={16}{x}^{{{2}}}-{32}{x}-{6}{x}+{12}$$
$$\displaystyle={16}{x}^{{{2}}}-{38}{x}+{12}$$
Thus, the multiplication of the expression $$\displaystyle{\left({8}{x}-{3}\right)}{\left({2}{x}-{4}\right)}$$ is $$16x^{2}-38x+12$$