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Solve dxdt+2x=2e−3t with initial condition x(0)=2
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Consider the provided differential equation,
Given dxdt+2x=2e−3t with initial condition x(0)=2
This is the ordinary differential equation.
Take Laplace on both the sides,
sLx(t)−x(0)+2Lx(t)=2s+3[Since , L(e−at)=1s+a]
Now, further simplified the above equation,
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By using Laplace transforms, solve the following differential equations subject to the given initial conditions. y"-4y'=-4te2t,y0=0,y'0=1
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