Find the inverse Laplace transformation for \frac{2s-11}{(s^2-4s+8)}

cistG

cistG

Answered question

2021-09-06

Find the inverse Laplace transformation for 2s11(s24s+8)

Answer & Explanation

Jayden-James Duffy

Jayden-James Duffy

Skilled2021-09-07Added 91 answers

Step 1
find the inverse Laplace transform for
2s11(s24s+8)

Step 2
Let,
F(s)=2s11(s24s+8)=2s11s24s+4+4
=2s11(s2)2+4=2(s112)(s2)2+4
=2[s(s2)2+4112(s2)2+4]
=2[s2+2(s2)2+4112(s2)2+4]
=2[s2(s2)2+4+2(s2)2+4112(s2)2+4]
=2[s2(s2)2+472(s2)2+4]
F(s)=2[s2(s2)2+2272(s2)2+22]
Now , apply inverse Laplace transform on both sides,
L1[F(s)]=2L1[s2(s2)2+2272(s2)2+22]
By using first shifting theorem,
F(t)=2e2tL1[ss2+2272s2+22]

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Differential Equations

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?