# Subtract the polynomials (10x^3-5x^2+3x-4)-(6x^3+4x^2-3x-1)

Subtract the polynomials $$\displaystyle{\left({10}{x}^{{3}}-{5}{x}^{{2}}+{3}{x}-{4}\right)}-{\left({6}{x}^{{3}}+{4}{x}^{{2}}-{3}{x}-{1}\right)}$$

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timbalemX
We have to subtract the following
Subtract the polynomials $$\displaystyle{\left({10}{x}^{{3}}-{5}{x}^{{2}}+{3}{x}-{4}\right)}-{\left({6}{x}^{{3}}+{4}{x}^{{2}}-{3}{x}-{1}\right)}$$
Solution: $$\displaystyle{\left({10}{x}^{{3}}-{5}{x}^{{2}}+{3}{x}-{4}\right)}-{\left({6}{x}^{{3}}+{4}{x}^{{2}}-{3}{x}-{1}\right)}$$
$$\displaystyle={10}{x}^{{3}}-{5}{x}^{{2}}+{3}{x}-{4}-{6}{x}^{{3}}-{4}{x}^{{2}}+{3}{x}+{1}$$
$$\displaystyle={4}{x}^{{3}}-{9}{x}^{{2}}+{6}{x}-{3}$$
Hence, $$\displaystyle{\left({10}{x}^{{3}}-{5}{x}^{{2}}+{3}{x}-{4}\right)}-{\left({6}{x}^{{3}}+{4}{x}^{{2}}-{3}{x}-{1}\right)}={4}{x}^{{3}}-{9}{x}^{{2}}+{6}{x}-{3}$$