Tazmin Horton
2021-09-17
Answered

Convert the equalities below equalities by adding sack variables. Use $s}_{1}\text{}\text{and}\text{}{s}_{2$ for your slack variables.

$3{x}_{1}+9{x}_{2}\le 42$ converts to () =42

$15{x}_{1}+7{x}_{2}\le 38$ converts to () = 38

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Leonard Stokes

Answered 2021-09-18
Author has **98** answers

Step 1

Solution: Given:

$3{x}_{1}+9{x}_{2}\le 42\to \left(1\right)$

$15{x}_{1}+7{x}_{2}\le 38\to \left(2\right)$

Now to equalize the above equation , we add$s}_{1}\text{}\text{and}\text{}{s}_{2$ to the above eqn (1) and (2) respectively,

$3{x}_{1}+9{x}_{2}+{s}_{1}=42\to \left(1a\right)$

$15{x}_{1}+7{x}_{2}+{s}_{2}=38\to \left(2f\right)$

Step 2

$\therefore$ For initial simplex , basis feasible solution in ${x}_{1}=0\text{}\text{and}\text{}{x}_{2}=0$

$\Rightarrow {s}_{1}=42\text{}\text{and}\text{}{s}_{2}=38$

So, answer.

$3{x}_{1}+9{x}_{2}+{s}_{1}=42$

$15{x}_{1}+7{x}_{2}+{s}_{2}=38$

Solution: Given:

Now to equalize the above equation , we add

Step 2

So, answer.

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