Step 1

Margin of Error can be calculated by:

\(\displaystyle{M}={z}\times\frac{\sigma}{\sqrt{{n}}}\)

where: z depends on the confidence interval with we are working,

Let's assume \(95\%\) as the confidence interval,

So, \(\displaystyle{z}={1.96}\)

Step 2

Here :

Standard deviation \(\displaystyle{\left(\sigma\right)}={50}\)

N is the no. of sample,

Hence,

We have:

\(\displaystyle{M}={1.96}\times\frac{50}{\sqrt{{25}}}\)

\(\displaystyle={1.96}\times{10}\)

\(\displaystyle={19.6}\)

Rounding to the nearest whole number we get:

\(\displaystyle{M}={20}\)

Hence,

Jo's margin of error is 20(rounded to the nearest whole number).

Margin of Error can be calculated by:

\(\displaystyle{M}={z}\times\frac{\sigma}{\sqrt{{n}}}\)

where: z depends on the confidence interval with we are working,

Let's assume \(95\%\) as the confidence interval,

So, \(\displaystyle{z}={1.96}\)

Step 2

Here :

Standard deviation \(\displaystyle{\left(\sigma\right)}={50}\)

N is the no. of sample,

Hence,

We have:

\(\displaystyle{M}={1.96}\times\frac{50}{\sqrt{{25}}}\)

\(\displaystyle={1.96}\times{10}\)

\(\displaystyle={19.6}\)

Rounding to the nearest whole number we get:

\(\displaystyle{M}={20}\)

Hence,

Jo's margin of error is 20(rounded to the nearest whole number).