# Scott wants to find a 95% confidence interval for the average GPA for Allegany College of Maryland students. He gets the records for 89 student. The r

Scott wants to find a $95\mathrm{%}$ confidence interval for the average GPA for Allegany College of Maryland students. He gets the records for 89 student. The results were roughly bell-shaped with a mean of 2.3 and standard deviation of 0.7. Construct a $95\mathrm{%}$ confidence interval in the form: Estimate $±$ margin of error.
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Demi-Leigh Barrera
Step 1
Confidence interval are of utmost importance in statistics. It forms an integral part of hypothesis testing.
Step 2
The estimate is the mean $=2.4$
The margin of error is $\frac{\sigma }{{\sqrt{n}}^{\tau }}0.025=\frac{0.7}{\sqrt{89}}\left(1.96\right)=0.4986$
n is the sample size, $\sigma$ is the standard deviation.