Urn 1 contains 7 red balls and 1 black ball. Urn 2 contains 1 red ball and 2 black balls. Urn 3 contains 5 red balls and 2 black balls. If an urn is selected at random and ball is drawn, find the probability that it will be red.

mattgondek4
2021-09-13
Answered

Urn 1 contains 7 red balls and 1 black ball. Urn 2 contains 1 red ball and 2 black balls. Urn 3 contains 5 red balls and 2 black balls. If an urn is selected at random and ball is drawn, find the probability that it will be red.

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Tuthornt

Answered 2021-09-14
Author has **107** answers

Urn 1 = 7 red balls and 1 black balls

Urn 2 = 1 red balls and 2 black balls

Urn 3 = 5 red balls and 2 black balls

There are 7+1+5 = 13 red balls.

There are a total of 7+1+5+1+2+2 = 18 balls

P(red) = (number of red balls)/(number of balls total)

P(red) =$\frac{13}{18}$

P(red) =$0.722$

Urn 2 = 1 red balls and 2 black balls

Urn 3 = 5 red balls and 2 black balls

There are 7+1+5 = 13 red balls.

There are a total of 7+1+5+1+2+2 = 18 balls

P(red) = (number of red balls)/(number of balls total)

P(red) =

P(red) =

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