Urn 1 contains 7 red balls and 1 black ball. Urn 2 contains 1 red ball and 2 black balls. Urn 3 contains 5 red balls and 2 black balls.

mattgondek4

mattgondek4

Answered question

2021-09-13

Seven red and one black ball are present in Urn 1. One red ball and two black balls are in Urn 2. Five red and two black balls are in urn number three. Calculate the likelihood that a red ball will be drawn if an urn is chosen at random and then drawn.

Answer & Explanation

Tuthornt

Tuthornt

Skilled2021-09-14Added 107 answers

Urn 1 = 7 red balls and 1 black balls
Urn 2 = 1 red balls and 2 black balls
Urn 3 = 5 red balls and 2 black balls
There are 7+1+5 = 13 red balls.
There are a total of 7+1+5+1+2+2 = 18 balls
P(red) = (number of red balls)/(number of balls total)
P(red) = 1318
P(red) = 0.722

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