Substract 9x^2y^2-3x^2-5 from the sum of -6x^2y^2-x^2-1 and 5x^2y^2+2x^2-1

Amari Flowers

Amari Flowers

Answered question

2021-09-06

Substract 9x2y23x25 from the sum of 6x2y2x21 and 5x2y2+2x21

Answer & Explanation

diskusje5

diskusje5

Skilled2021-09-07Added 82 answers

First, find the sum of the polynomials 6x2y2x21 and 5x2y2+2x21
Then,
(6x2y2x21)+(5x2y2+2x21)=6x2y2+5x2y2x2+2x211
=(6+5)x2y2+(1+2)x22
=x2y2+x22
Therefore, the sum of the polynomials 6x2y2x21 and 5x2y2+2x21 is x2y2+x22
Now, subtract 9x2y23x25 from x2y2+x22
So,
(x2y2+x22)(9x2y23x25)=x2y2+x229x2y2+3x2+5
=x2y29x2y2+x2+3x22+5
=(19)x2y2+(1+3)x2+52
=10x2y2+4x2+3
Hence, the required polynomial is 10x2y2+4x2+3

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