Question

Find the exact length of the curve. x = \frac{y^4}{8} + \frac{1}{4y^2} , 1 \leq y \leq 2

Integrals
ANSWERED
asked 2021-09-03
Find the exact length of the curve. \(\displaystyle{x}={\frac{{{y}^{{4}}}}{{{8}}}}+{\frac{{{1}}}{{{4}{y}^{{2}}}}},{1}\leq{y}\leq{2}\)

Expert Answers (1)

2021-09-04
Length of the curve
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