tan^2 theta-sin^2 theta=tan^2 theta sin theta

Emeli Hagan

Emeli Hagan

Answered question

2021-09-09

tan2θsin2θ=tan2θsinθ

Answer & Explanation

okomgcae

okomgcae

Skilled2021-09-10Added 93 answers

Work on the left side. Use the quotient identity for tangent: tan2θsin2θ=(sin2θcos2θ)sin2θ

Factor out sin2θ: tan2θsin2θ=sin2θ((1cos2θ)1)

tan2θsin2θ=sin2θ(1cos2θcos2θ)

Use the Pythagorean identity: sin2θ+cos2θ=1

tan2θsin2θ=sin2θ(sin2θcos2θ)

tan2θsin2θ=sin2θtan2θ

or tan2θsin2θ=tan2θsin2θ

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