David drives to school in rush hour traffic and averages 32 mph. He returns home in mid-afternoon when there is less traffic and averages 48 mph.

slaggingV 2021-09-04 Answered
David drives to school in rush hour traffic and averages 32 mph. He returns home in mid-afternoon when there is less traffic and averages 48 mph. What is the distance between his home and school if the total traveling time is 1 hr 15 min?
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Expert Answer

crocolylec
Answered 2021-09-05 Author has 100 answers

DrtTo schoold32t1To housed48t2

The table above summarizes the information of the given problem

Using D=rt or the formula for the relationship of distance, rate,and time, then d=32t1
d32=t1 and d=48t2
d48=t2 Since the total time is given as 1 hour and 15 minutes (or11560=114=54hours) , then t1+t2=54
d32+d48=54
96(d32+d48)=(54)96 (multiply by the LCD)
3(d)+2(d)=5(24)
3d+2d=120
5d120
5d5=1205
d=24
Hence, the distance, d, between house and school is 24 miles.

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