 # Marcus rowed 20 miles downstream in 2 hours. The trip back, however, took him 4 hours. Find the rate that Marcus rows in still water and the rate of t geduiwelh 2021-01-27 Answered
Marcus rowed 20 miles downstream in 2 hours. The trip back, however, took him 4 hours. Find the rate that Marcus rows in still water and the rate of the current. If x is Marcuss
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From given,
Downstream equation is: Distance 20, Rate Time 2
Upstream equation is: Distance 20, Rate Time 4
It is that, the distance formula is $D=RT.$
That implies,
$20=4\left(x-y\right)$
$20=2\left(x+y\right)$
Thus, the downstream equation is $2x+2y=20$ (1)
The upstream equation is $4x-4y=20$ (2)
Multiply equation (1) by 2 and add it with (2)
$4x+4x=40+4x-4y=20$
$=8x=60$
$x=\frac{60}{8}$
$x=7.5$
The rate that Marcus rows in still water and the rate of the curent 7.5 mph
The speed of the river current is,
$4\left(7.5\right)-4y=20$
$30-4y=20$
$-4y=20-30$
$-4y=-10$
$y=2.5$
Thus, the speed of the river current is 2.5 mph