Find the required information and graph: displaystyle{2}{x}^{2}+{2}{y}^{2}+{2}{x}+{14}{y}+{17}={0}

ankarskogC 2021-02-25 Answered
Find the required information and graph:
2x2+2y2+2x+14y+17=0
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Expert Answer

Nicole Conner
Answered 2021-02-26 Author has 97 answers
Step 1
Consider the provided equation,
2x2+2y2+2x+14y+17=0
Classify the conic section and find the center.
We can write as,
2x2+2x+2y2+14y+17=0
2(x2+x)+2(y2+7y)=17
(x2+x)+(y2+7y)=172
(x2+x+14)+(y2+7y+494)=172+494+14
Step 2
Simplifying further,
(x+12)2+(y+72)2=4
(x(12))2+(y(72))2=22
(xa)2+(yb)2=r2 is the circle equation with radius r, centered at (a, b).
Thus, this is a circle.
So, the center or the circle (12,72).

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Jeffrey Jordon
Answered 2021-10-26 Author has 2495 answers

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