The conic for the equation displaystyle{left({x}+{2}right)}^{2}+{left({y}-{1}right)}^{2}={4} and also describe the translation of the conic from the standard position.

York 2021-02-11 Answered
The conic for the equation (x+2)2+(y1)2=4 and also describe the translation of the conic from the standard position.
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Expert Answer

Raheem Donnelly
Answered 2021-02-12 Author has 75 answers
Consider the equation,
(x+2)2+(y1)2=4
The above equation is also written as follows,
(x+2)2+(y1)2=22
Now compare the above equation with the standard form of the equation of the circle, that is (xh)2+(yk)2=r2.
So,
h=2,k=1andr=2
Thus, the equation (x+2)2+(y1)2=4 is the equation of circle with center at (-2, 1)
and radius r=2 as shown below,
Therefore, the graph has been shifted 1 unit upward and 2 units to the left from the standard position.
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