Let X be a normal random variable with mean 12 and variance 4. Find the value of c such that P{X>c}=.10.

Tahmid Knox 2021-08-20 Answered
Let X be a normal random variable with mean 12 and variance 4. Find the value of c such that P{X>c}=.10.
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Expert Answer

Aamina Herring
Answered 2021-08-21 Author has 85 answers
Given: X is normal random variable with mean μ=12 variance σ2=4
To find: Value of c such that P[X>c]=0.10
Solution: We have
P[X>c]=0.1
P[Xc]=10.1=0.9
P[Xμσc122]=0.9
P[Zc122]=0.9
Φ(c122)=0.9
c122=1.28
c12=2.56
c=14.56
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