Find sec^2 θ - tan^2 θ.

pancha3

pancha3

Answered question

2021-08-21

Find 1secθtanθ+1secθ+tanθ

Answer & Explanation

Nicole Conner

Nicole Conner

Skilled2021-08-22Added 97 answers

We are given: 1secθtanθ+1secθ+tanθ

Rewrite using the LCD which is (secθtanθ)(secθ+tanθ)=1secθtanθ(secθ+tanθsecθ+tanθ)+1secθ+tanθ(secθtanθsecθtanθ)=(secθ+tanθ)+(secθtanθ)sec2θtan2θ

Recall that sec2θ=1+tan2θ so sec2θtan2θ=1=2secθ1=2secθ

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