Find the value of \tan^{-1}\sqrt{3}-\sec^{-1}(-2)

e1s2kat26

e1s2kat26

Answered question

2021-08-15

Find the value of tan13sec1(2)

Answer & Explanation

Usamah Prosser

Usamah Prosser

Skilled2021-08-16Added 86 answers

We use Trigonometry table to find angle
z=tan13sec1(2)
z=x+y
x=tan3
tanx=3
tanx=tanπ3
x=π3
y=sec1(2)
y=[πsec12]
y=[ππ3]
y=[2π3]
z=x+y
z=π32π3
z=π2π3
z=π3

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