How do you solve \sin x\cos x =\frac{1}{2} for x in the interval [0,2

Jaya Legge 2021-08-16 Answered
How do you solve sinxcosx=12 for x in the interval [0,2π)?
You can still ask an expert for help

Want to know more about Trigonometry?

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

dieseisB
Answered 2021-08-17 Author has 85 answers
sin2x=2sinxcosx
sinxcosx=(12)sin2x=12sin2x=1
sin2x=1arcsin2x=π4x=π4
Check:sinπ4cosπ4=(22)(22)=24=12 Perfect!
Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more