# Parametric equations and a value for the parameter t are given x = t^2+3,y=6-t^3.t=

Parametric equations and a value for the parameter t are given $$\displaystyle{x}={t}^{{2}}+{3},{y}={6}-{t}^{{3}}$$.t=2
Find the coordinates of the point on the plane curve described by the parametric equations corresponding to the given value of t.

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wheezym
For t=2,$$\displaystyle{x}={t}^{{2}}+{3}={2}^{{2}}+{3}={4}+{3}={7}$$
For t=2,$$\displaystyle{y}={6}-{t}^{{3}}={6}-{2}^{{3}}={6}-{8}=-{2}$$
So, the coordinate points(x,y)=(7,-2)