int 6x^2(x^3+2)^99 dx

Maiclubk 2021-08-17 Answered
6x2(x3+2)99dx
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opsadnojD
Answered 2021-08-18 Author has 95 answers
Let u=x3+2 Then du=3x2dx the integral has a 6x2 so multiplying both sides of du=3x2 by 2 gives 2 du=6x2dx. Replacing x3+2 with u and replacing 6x2dx with 2 du then gives:
6x2(x3+2)99dx=(x3+2)99(6x2dx)
=u99(2du)
=2u99du Integrating using the power rule then gives 2u99du=2u100100+C=u10050+C.
Substituting x3+2 for u then gives (x3+2)10050+C
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