# Explain how to find the value of sin 390^{\circ} using periodic properties.

Explain how to find the value of sin $$\displaystyle{390}^{{\circ}}$$ using periodic properties.

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Step 1
Use $$\displaystyle{\sin{{\left({360}+\alpha\right)}}}={\sin{\alpha}}$$
Step 2
$$\displaystyle{\sin{{390}}}$$
$$\displaystyle={\sin{{\left({360}+{30}\right)}}}$$
$$\displaystyle={\sin{{30}}}$$
$$\displaystyle={\frac{{{1}}}{{{2}}}}={0.5}$$