# Explain how to find the value of sin 390^{\circ} using periodic properties.

Explain how to find the value of sin ${390}^{\circ }$ using periodic properties.
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Step 1
Use $\mathrm{sin}\left(360+\alpha \right)=\mathrm{sin}\alpha$
Step 2
$\mathrm{sin}390$
$=\mathrm{sin}\left(360+30\right)$
$=\mathrm{sin}30$
$=\frac{1}{2}=0.5$