(t + 2)^2/3 + 3(t + 2)^1/3 - 10 =

Tazmin Horton 2021-08-17 Answered
(t+2)23+3(t+2)1310=0
how do i solve?
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Expert Answer

Dora
Answered 2021-08-18 Author has 98 answers

Given equation is: (t+2)23+3(t+2)1310=0(1)
Let (t+2)13=x
(t+2)13(t+2)13+3(t+2)1310=0
xx+3x10=0
x2+3x10=0(2)
Solving the quadratic equation (2) x2+3x10=0
x2+5x2x10
x(x+5)2(x+5)=0
(x+5)(x2)=0
x=−5 and x=2
Putting the value of x : (t+2)13=x
(t+2)13=2
cubing both the sides (t+2)=23
(t+2)=8
t=82=6
t=6
(t+2)13=5
(t+2)=125
t=1252=127
Thus the value of t are 6 and -127

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Jeffrey Jordon
Answered 2021-10-10 Author has 2027 answers

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