# The roots of the equation of a quadratic function are

The roots of the equation of a quadratic function are x=3 and x=5. Find an equation for the quadratic function that contains the point(1,-24).
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hesgidiauE
The roots are x=3 and x=5
f(x) =a(x-3)(x-5)
It passes through (1,-24)
-24=a(1-3)(1-5)
-24=a(-2)(-4)=8a
$a=-\frac{24}{8}a=-3$
f(x)=-3(x-3)(x-5)
=$-3\left({x}^{2}-5x-3x+15\right)$
$f\left(x\right)=-3{x}^{2}+24x-45$
Jeffrey Jordon