To find: The sum of the given arithmetic sequence. Given: the

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Answered question

2021-08-16

To find: The sum of the given arithmetic sequence.
Given: the sequence n=190(32n)

Answer & Explanation

au4gsf

au4gsf

Skilled2021-08-17Added 95 answers

Formula used:
The formula for the summation of a polynomial with degree 1 is, k=1nk=n2(n+1).(1)
The formula for the summation of a constant is, k=1nc=cn..(2)
Calculation:
To find the sum of the arithmetic sequence, i.e, to find,
Sn=n=190(32n)
Write n=19032n as follows,
n=190(32n)=n=19032n=190n
Now to find n=1903,
Substitute the values of n in equation (2)
We get,
n=1903
=3(90)
=270
Now to find the 2n=190n
Substitute the values of n in equation (1).
We get,
2n=190n
=2(90(90+1)2)
=2(90×912)
=8190
Then,
n=1903+2n=190n=2708190
=7920
Hence
n=190(32n)=7920.

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