# 5(10^x−6)=7

$5\left({10}^{x}-6\right)=7$
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hajavaF
We are given: $5\left({10}^{x}-6\right)=7$
Divide both sides by 5: ${10}^{x}-6=1.4$
Take the (common) logarithm of both sides: ${\mathrm{log}10}^{x}-6=\mathrm{log}1.4$
Recall that $\mathrm{log}b\cdot {b}^{x}=x$ and since the common logarithm is base 10, we write: $x-6=\mathrm{log}1.4$
Add 6 to both sides: $x=6+\mathrm{log}1.4\sim 6.146$