No, it's not. The form of a linear equation:

az+by=c

Since x in the given equation is raised to the power of 2, it's not linear, it's quadratic.

az+by=c

Since x in the given equation is raised to the power of 2, it's not linear, it's quadratic.

asked 2021-05-14

Contain linear equations with constants in denominators. Solve each equation.
\(\displaystyle\frac{{{x}+{1}}}{{4}}=\frac{{1}}{{6}}+\frac{{{2}-{x}}}{{3}}\)

asked 2021-07-02

Contain linear equations with constants in denominators. Solve each equation.
\(\displaystyle\frac{{x}}{{5}}-\frac{{1}}{{2}}=\frac{{x}}{{6}}\)

asked 2021-02-09

A real-estate agent is trying to determine the relationship between the distance a 3-bedroom home is from New York City and its average selling price. He records the data for 6 homes shown below.
Linear or Quadratic?
Equation:
Approximate cost of home 90 miles from NYC?

asked 2021-05-05

Contain linear equations with constants in denominators. Solve each equation.
\(\displaystyle\frac{{x}}{{5}}={\left(\frac{{x}}{{6}}+{1}\right)}\)

asked 2020-10-23

\(\displaystyle{\left({X}_{{1}},{Y}_{{1}}\right)}={\left({4},{8}\right)},{\left({X}_{{2}},{Y}_{{2}}\right)}={\left({6},-{9}\right)}\)

asked 2021-05-13

Graph the linear equations. Then use the graph to estimate how many solutions the equations share. y = 4x + 9 4x - y = 1

asked 2021-06-02

Contain linear equations with constants in denominators. Solve each equation.
\(\displaystyle\frac{{{x}+{1}}}{{3}}={5}-\frac{{{x}+{2}}}{{7}}\)