Use the quadratic formula ${y}^{2}-7y-5=0$

pedzenekO
2021-08-15
Answered

Use the quadratic formula ${y}^{2}-7y-5=0$

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likvau

Answered 2021-08-16
Author has **75** answers

Solve for y over the real numbers:

${y}^{2}-7y-5=0$

Hint: Using the quadratic formula, solve for y.

$\left\{y\right\}=\frac{\{\left\{7\right\}\pm \sqrt{\{{\left\{(-\left\{7\right\})\right\}}^{2}-\left\{4\right\}\left\{(-\left\{5\right\})\right\}\}}\}}{\left\{2\right\}}=\frac{\{\left\{7\right\}\pm \sqrt{\{\left\{49\right\}+\left\{20\right\}\}}\}}{\left\{2\right\}}=\frac{\{\left\{7\right\}\pm \sqrt{\left\{\left\{69\right\}\right\}}\}}{\left\{2\right\}}$

Answer:

$\left\{y\right\}=\frac{\{\left\{7\right\}+\sqrt{\left\{\left\{69\right\}\right\}}\}}{\left\{2\right\}}\left\{{\textstyle \phantom{\rule{1em}{0ex}}}\text{or}{\textstyle \phantom{\rule{1em}{0ex}}}\right\}\left\{y\right\}=\frac{\{\left\{7\right\}-\sqrt{\left\{\left\{69\right\}\right\}}\}}{\left\{2\right\}}$

Hint: Using the quadratic formula, solve for y.

Answer:

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