# Use the quadratic formula y^{2}-7y-5=0

Use the quadratic formula ${y}^{2}-7y-5=0$
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Solve for y over the real numbers:
${y}^{2}-7y-5=0$
Hint: Using the quadratic formula, solve for y.
$\left\{y\right\}=\frac{\left\{\left\{7\right\}±\sqrt{\left\{{\left\{\left(-\left\{7\right\}\right)\right\}}^{2}-\left\{4\right\}\left\{\left(-\left\{5\right\}\right)\right\}\right\}}\right\}}{\left\{2\right\}}=\frac{\left\{\left\{7\right\}±\sqrt{\left\{\left\{49\right\}+\left\{20\right\}\right\}}\right\}}{\left\{2\right\}}=\frac{\left\{\left\{7\right\}±\sqrt{\left\{\left\{69\right\}\right\}}\right\}}{\left\{2\right\}}$
$\left\{y\right\}=\frac{\left\{\left\{7\right\}+\sqrt{\left\{\left\{69\right\}\right\}}\right\}}{\left\{2\right\}}\left\{\phantom{\rule{1em}{0ex}}\text{or}\phantom{\rule{1em}{0ex}}\right\}\left\{y\right\}=\frac{\left\{\left\{7\right\}-\sqrt{\left\{\left\{69\right\}\right\}}\right\}}{\left\{2\right\}}$