# Solve inequality, please: (3 – x)/(x + 5) >= 1

Solve inequality, please: $$\displaystyle\frac{{{3}–{x}}}{{{x}+{5}}}\ge{1}$$

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Usamah Prosser
$$\displaystyle\frac{{{3}–{x}}}{{{x}+{5}}}\ge{1}$$
$$\displaystyle\frac{{{3}–{x}}}{{{x}+{5}}}–{1}\ge{0}$$
$$\displaystyle{\left({3}–{x}\right)}–{\left({x}+{5}\right)}\frac{{)}}{{{x}+{5}}}\ge{0}$$
$$\displaystyle\frac{{-{2}{\left({x}+{1}\right)}}}{{{x}+{5}}}\ge{0}$$
$$\displaystyle\frac{{{x}+{1}}}{{{x}+{5}}}\ge{0}$$, so
$$\displaystyle{f{{\left({x}\right)}}}=\frac{{{x}+{1}}}{{{x}+{5}}}$$
$$\displaystyle{x}=-{5},{x}=-{1}$$