# Solve inequality 1/(x^2 – 14x + 40) <= 0

Solve inequality $$\displaystyle\frac{{1}}{{{x}^{{2}}–{14}{x}+{40}}}\le{0}$$

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yunitsiL
$$\displaystyle\frac{{1}}{{{x}^{{2}}–{14}{x}+{40}}}\le{0}$$
$$\displaystyle\frac{{1}}{{{\left({x}–{4}\right)}{\left({x}–{10}\right)}}}\le{0}$$
This expression is undefined for x = 10 and x = 4, so these are boundary points. The related equation has no real zeros.