Use the point (-2. 3) and the slope m = 3 to get the point-slope form of the equation of the line:

\(\displaystyle{y}–{3}={3}{\left({x}–{\left(-{2}\right)}\right)}\)

\(\displaystyle{y}–{3}={3}{\left({x}+{2}\right)}\)

\(\displaystyle{y}–{3}={3}{x}+{6}\)

\(\displaystyle{y}={3}{x}+{9}\)

\(\displaystyle{y}–{3}={3}{\left({x}–{\left(-{2}\right)}\right)}\)

\(\displaystyle{y}–{3}={3}{\left({x}+{2}\right)}\)

\(\displaystyle{y}–{3}={3}{x}+{6}\)

\(\displaystyle{y}={3}{x}+{9}\)