Suppose \lambda is an eigenvalue of the n \times n

Josalynn

Josalynn

Answered question

2021-08-17

Suppose λ is an eigenvalue of the n×n matrix A. If u and v are eigenvectors of A corresponding to λ, which of the following statement MUST be false?
1)λ=0
2) u and v are scalars multiple of each other.
3) nullity (AλI)=0
4) 7v3u is also an eigenvector of A.

Answer & Explanation

broliY

broliY

Skilled2021-08-18Added 97 answers

Step 1
In the question we have to find falsa statement.
Step 2
Result - option d
Given that u and v are eigen vectors of A(n×n) matrix.
a) λ=0 - true eigen values can be zero or non zero or positive or negative too.
b) u and v are scalar multiple of each other - true because eigen vactor are written as [1,3]t or any quantity which implies eigen vectors are scalar multiples.
c) nullity AλI=0 - true as eigen values are found by putting eigen values in this form.
d) 7v3u is also a eigen vector of matrix A - false because eigen vectors can not be calculated by taking sum, difference or any calculus.

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