A polynomial P is given. (a) Factor P into linear

chillywilly12a

chillywilly12a

Answered question

2021-08-11

A polynomial P is given. (a) Factor P into linear and irreducible quadratic factors with real coefficients. (b) Factor P completely into linear factors with complex coefficients.
P(x)=x4+8x29

Answer & Explanation

Dora

Dora

Skilled2021-08-12Added 98 answers

a) To find: The factorization of the polynomial P(x) in linear and irreducible quadratic factors with real coefficients.
Given information:
The polynomial P(x) is,
P(x)=x4+8x29
Concept used:
Linear and Quadratic Factors Theorem:
Any polynomial that has real coefficients can be factored into the product of linear and irreducible quadratic factors.
Calculation:
The given polynomial P(x) is,
P(x)=x4+8x29
Rewrite the above polynomial as,
P(x)=x4+9x2x29
Now, factor the polynomial P(x) as,
P(x)=x2(x2+9)1(x2+9)
=(x21)(x2+9)
=(x1)(x+1)(x2+9)
The factor (x1) and (x+1) are linear factors with real zeros.
The factor (x2+9) is irreducible, since it has no real zeros.
Conclusion:
Thus, the factored form of the polynomial P(x) that has linear and irreducible quadratic factors is (x1)(x+1)(x2+9)
b) To find: The factors of the polynomial P(x) that has linear factors with complex coefficients.
Given: The polynomial P(x) is,
P(x)=x4+8x29
Calculation:
From part (a) the factored form of the polynomial P(x) is,
P(x)=(x1)(x+1)(x2+9)
Now, factor the remaining quadratic factor to obtain the complete factorization as,
P(x)=(x1)(x+1)(x2+9)
=(x1)(x+1)(x2(3i)2)
=(x1)(x+1)(x3i)(x+3i)
The above factors are linear factors with complex coefficients.
Conclusion:
Thus, the factored form of the polynomial P(x) that has linear factors is (x1)(x+1)(x3i)(x+3i).

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