In this case, the circle fits inside the square, touching its four sides. So, the side of the square is equal to the diameter of the circle which is 2(8)=16 feet. Hence, the area of the square is:

\(\displaystyle{A}={s}^{{2}}\)

\(\displaystyle{A}={16}^{{2}}\)

A=256 square feet

\(\displaystyle{A}={s}^{{2}}\)

\(\displaystyle{A}={16}^{{2}}\)

A=256 square feet