What is the radius and center for (x-2)^{2}+y^{2}=16? A. r=16. center

beljuA

beljuA

Answered question

2021-08-09

What is the radius and center for (x2)2+y2=16?
A. r=16. center is (2,0)
B. r=4. center is (-2,0)
C. r=16. center is (-2,0)
D. r=4. center is (2,0)

Answer & Explanation

Yusuf Keller

Yusuf Keller

Skilled2021-08-10Added 90 answers

Step 1
Given equation is (x2)2+y2=16
find radius and center
Step 2
given equation is a circle
standard form of an equation of a circle is (xh)2+(yk)2=r2
center =(h,k)
radius =r
lets write the given equation in standard form
(x2)2+(y0)2=42
center =(2,0)
radius =r=4
Thus D is a correct option.

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