Step 1

Topic- circles and square

Step 2

Circle radius

\(\displaystyle{R}=?\)

here side of square

\(\displaystyle{a}={8}{c}{m}\)

\(\displaystyle\Rightarrow{o}{m}={1}{m}=\frac{{a}}{{2}}={4}{c}{m}\)

using pythagors theorem

\(\displaystyle{R}^{{{2}}}={\left({o}{m}\right)}^{{{2}}}+{\left(\pm\right)}^{{{2}}}\)

\(\displaystyle\Rightarrow{R}^{{{2}}}={\left({4}\right)}^{{{2}}}+{\left({4}\right)}^{{{2}}}\)

\(\displaystyle\Rightarrow{R}^{{{2}}}={32}\)

\(\displaystyle\Rightarrow{R}={4}\sqrt{{{2}}}{c}{m}\)

Topic- circles and square

Step 2

Circle radius

\(\displaystyle{R}=?\)

here side of square

\(\displaystyle{a}={8}{c}{m}\)

\(\displaystyle\Rightarrow{o}{m}={1}{m}=\frac{{a}}{{2}}={4}{c}{m}\)

using pythagors theorem

\(\displaystyle{R}^{{{2}}}={\left({o}{m}\right)}^{{{2}}}+{\left(\pm\right)}^{{{2}}}\)

\(\displaystyle\Rightarrow{R}^{{{2}}}={\left({4}\right)}^{{{2}}}+{\left({4}\right)}^{{{2}}}\)

\(\displaystyle\Rightarrow{R}^{{{2}}}={32}\)

\(\displaystyle\Rightarrow{R}={4}\sqrt{{{2}}}{c}{m}\)