berggansS

Answered 2021-08-09
Author has **23660** answers

asked 2021-05-17

The yield strength of CP titanium welds was measured for welds cooled at rates of \(10^{\circ} \mathrm{C} ; \mathrm{s}, 15^{\circ} \mathrm{C} ; \mathrm{s}, \text{ and } 28^{\circ} \mathrm{C} ; \mathrm{s}\). The results are presented in the following table. (Based on the article “Advances in Oxygen Equivalence Equations for Predicting the Properties of Titanium Welds,” D. Harwig, W. Ittiwattana, and H. Castner, The Welding Journal, 2001:126s-136s.)

\(\begin{matrix}
\hline
\text{Cooling Rate}&\text{Yiled Strengths}\\
\hline
10&71.00&75.00&79.67&81.00&75.50&72.50&73.50&78.50&78.50\\
15&63.00&68.00&73.00&76.00&79.67&81.00\\
28&68.65&73.70&78.40&84.40&91.20&87.15&77.20&80.70&84.85&
88.40\\
\hline
\end{matrix}\)

a. Construct an ANOVA table. You may give a range for the P-value. b. Can you conclude that the yield strength of CP titanium welds varies with the cooling rate?

asked 2021-05-26

The yield strength of CP titanium welds was measured for welds cooled at rates of 10^{\circ} \mathrm{C} / \mathrm{s}, 15^{\circ} \mathrm{C} / \mathrm{s}, and 28^{\circ} \mathrm{C} / \mathrm{s}. The results are presented in the following table. (Based on the article “Advances in Oxygen Equivalence Equations for Predicting the Properties of Titanium Welds,” D. Harwig, W. Ittiwattana, and H. Castner, The Welding Journal, 2001:126s-136s.) Cooling Rate 101528amp;
Yield Strengths amp;71.00amp;63.00amp;68.65amp;75.00amp;68.00amp;73.70amp;79.67amp;73.00amp;78.40amp;81.00amp;76.00amp;84.40amp;75.50amp;79.67amp;91.20amp;72.50amp;81.00amp;87.15amp;73.50amp;amp;77.20amp;78.50amp;amp;80.70amp;78.50amp;amp;84.85amp;88.40
a. Construct an ANOVA table. You may give a range for the P-value. b. Can you conclude that the yield strength of CP titanium welds varies with the cooling rate?

asked 2021-02-25

We will now add support for register-memory ALU operations to the classic five-stage RISC pipeline. To offset this increase in complexity, all memory addressing will be restricted to register indirect (i.e., all addresses are simply a value held in a register; no offset or displacement may be added to the register value). For example, the register-memory instruction add x4, x5, (x1) means add the contents of register x5 to the contents of the memory location with address equal to the value in register x1 and put the sum in register x4. Register-register ALU operations are unchanged. The following items apply to the integer RISC pipeline:

a. List a rearranged order of the five traditional stages of the RISC pipeline that will support register-memory operations implemented exclusively by register indirect addressing.

b. Describe what new forwarding paths are needed for the rearranged pipeline by stating the source, destination, and information transferred on each needed new path.

c. For the reordered stages of the RISC pipeline, what new data hazards are created by this addressing mode? Give an instruction sequence illustrating each new hazard.

d. List all of the ways that the RISC pipeline with register-memory ALU operations can have a different instruction count for a given program than the original RISC pipeline. Give a pair of specific instruction sequences, one for the original pipeline and one for the rearranged pipeline, to illustrate each way.

Hint for (d): Give a pair of instruction sequences where the RISC pipeline has “more” instructions than the reg-mem architecture. Also give a pair of instruction sequences where the RISC pipeline has “fewer” instructions than the reg-mem architecture.

a. List a rearranged order of the five traditional stages of the RISC pipeline that will support register-memory operations implemented exclusively by register indirect addressing.

b. Describe what new forwarding paths are needed for the rearranged pipeline by stating the source, destination, and information transferred on each needed new path.

c. For the reordered stages of the RISC pipeline, what new data hazards are created by this addressing mode? Give an instruction sequence illustrating each new hazard.

d. List all of the ways that the RISC pipeline with register-memory ALU operations can have a different instruction count for a given program than the original RISC pipeline. Give a pair of specific instruction sequences, one for the original pipeline and one for the rearranged pipeline, to illustrate each way.

Hint for (d): Give a pair of instruction sequences where the RISC pipeline has “more” instructions than the reg-mem architecture. Also give a pair of instruction sequences where the RISC pipeline has “fewer” instructions than the reg-mem architecture.

asked 2021-06-05

Use the following Normal Distribution table to calculate the area under the Normal Curve (Shaded area in the Figure) when \(Z=1.3\) and \(H=0.05\);

Assume that you do not have vales of the area beyond \(z=1.2\) in the table; i.e. you may need to use the extrapolation.

Check your calculated value and compare with the values in the table \([for\ z=1.3\ and\ H=0.05]\).

Calculate your percentage of error in the estimation.

How do I solve this problem using extrapolation?

\(\begin{array}{|c|c|}\hline Z+H & Prob. & Extrapolation \\ \hline 1.20000 & 0.38490 & Differences \\ \hline 1.21000 & 0.38690 & 0.00200 \\ \hline 1.22000 & 0.38880 & 0.00190 \\ \hline 1.23000 & 0.39070 & 0.00190 \\ \hline 1.24000 & 0.39250 & 0.00180 \\ \hline 1.25000 & 0.39440 & 0.00190 \\ \hline 1.26000 & 0.39620 & 0.00180 \\ \hline 1.27000 & 0.39800 & 0.00180 \\ \hline 1.28000 & 0.39970 & 0.00170 \\ \hline 1.29000 & 0.40150 & 0.00180 \\ \hline 1.30000 & 0.40320 & 0.00170 \\ \hline 1.31000 & 0.40490 & 0.00170 \\ \hline 1.32000 & 0.40660 & 0.00170 \\ \hline 1.33000 & 0.40830 & 0.00170 \\ \hline 1.34000 & 0.41010 & 0.00180 \\ \hline 1.35000 & 0.41190 & 0.00180 \\ \hline \end{array}\)

Assume that you do not have vales of the area beyond \(z=1.2\) in the table; i.e. you may need to use the extrapolation.

Check your calculated value and compare with the values in the table \([for\ z=1.3\ and\ H=0.05]\).

Calculate your percentage of error in the estimation.

How do I solve this problem using extrapolation?

\(\begin{array}{|c|c|}\hline Z+H & Prob. & Extrapolation \\ \hline 1.20000 & 0.38490 & Differences \\ \hline 1.21000 & 0.38690 & 0.00200 \\ \hline 1.22000 & 0.38880 & 0.00190 \\ \hline 1.23000 & 0.39070 & 0.00190 \\ \hline 1.24000 & 0.39250 & 0.00180 \\ \hline 1.25000 & 0.39440 & 0.00190 \\ \hline 1.26000 & 0.39620 & 0.00180 \\ \hline 1.27000 & 0.39800 & 0.00180 \\ \hline 1.28000 & 0.39970 & 0.00170 \\ \hline 1.29000 & 0.40150 & 0.00180 \\ \hline 1.30000 & 0.40320 & 0.00170 \\ \hline 1.31000 & 0.40490 & 0.00170 \\ \hline 1.32000 & 0.40660 & 0.00170 \\ \hline 1.33000 & 0.40830 & 0.00170 \\ \hline 1.34000 & 0.41010 & 0.00180 \\ \hline 1.35000 & 0.41190 & 0.00180 \\ \hline \end{array}\)

asked 2021-09-22

The equations \(\displaystyle{y}=-{x}+{4}{\quad\text{and}\quad}{y}={12}{x}-{8}{y}\)

\(= 21x−8\) form a system of linear equations.

The table below shows the y-value for each equation at six different values of x. \(xy=−x+4y=12x−804−822−740−66−2−58−4−410−6−3\)

What can you conclude from the table?

A. The system has one solution, when x=0.

B. The system has one solution, when x=4.

C. The system has one solution, when x=8.

D. The system has no solution.

asked 2020-12-05

Use the first variable for the x-axis. Based on the scatterplot, what do you conclude about a linear correlation?

The table li sts che t sizes (di stance around chest in inches) and weights (pounds) of anesthetized bears that were measured.

\(\begin{array}{|c|c|}\hline \text{Chest(in.)} & 26 & 45 & 54 & 49 & 35 & 41 & 41 \\ \hline \text{Weight(lb)} & 80 & 344 & 416 & 348 & 166 & 220 & 262 \\ \hline \end{array}\)