Question

Given discrete math A = \begin{bmatrix}1 & 1 & 1

Discrete math
ANSWERED
asked 2021-08-10

Given discrete math \({A}=\begin{bmatrix}{1}&{1}&{1}\\{1}&{0}&{1}\\{1}&{1}&\end{bmatrix} {B}=\begin{bmatrix}{1}&{1}&{0}\\{1}&{1}&{1}\\{1}&{0}&{0}\end{bmatrix}\)
Find A

Answers (1)

2021-08-11

Solution \({A}=\begin{bmatrix}{1}&{1}&{1}\\{1}&{0}&{1}\\{1}&{1}&{0}\end{bmatrix}\)
\(\displaystyle{A}^{{2}}=\begin{bmatrix}{1}&{1}&{1}\\{1}&{0}&{1}\\{1}&{1}&0\end{bmatrix}\begin{bmatrix}{1}&{1}&{1}\\{1}&{0}&{1}\\{1}&{1}&{0}\end{bmatrix}\)
\(\displaystyle{A}^{{2}}=\begin{bmatrix}{3}&{2}&{2}\\{2}&{2}&{1}\\{2}&{1}&{2}\end{bmatrix}\)
\(\displaystyle{A}^{{3}}=\begin{bmatrix}{3}&{2}&{2}\\{2}&{2}&{1}\\{2}&{1}&{2}\end{bmatrix}\begin{bmatrix}{1}&{1}&{1}\\{1}&{0}&{1}\\{1}&{1}&{0}\end{bmatrix}\)
\(\displaystyle{A}^{{3}}=\begin{bmatrix}{7}&{5}&{5}\\{5}&{3}&{4}\\{5}&{4}&{3}\end{bmatrix} \)

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