Get the answer to "Sketch the following conic sections: 42−4y+8−4x2=0"

smileycellist2

Answered question

2021-08-15

Sketch the following conic sections:

4^{2} - 4 y + 8 - 4 x^{2} = 0

odgovoreh

Skilled2021-08-16Added 107 answers

Step 1
Given Equation:

y^{2} - 4 y + 8 - 4 x^{2} = 0

Converting the above equation in Standard hyperbola form standard form

\frac{{(x - h)}^{2}}{a^{2}} - \frac{{(y - k)}^{2}}{b^{2}} = 1

The above equation in Standard form

x^{2} - \frac{{(y - 2)}^{2}}{4} = 1

comparing with the standard form we have

h = 0, a = 1, k = 2, b = 2

Step 2
The graph of the above equation is shown below

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