Question

# Suppose we choose one of these players at random. What is the probability that the player has arthritis?

Two-way tables

A study in Sweden looked at former elite soccer players, people who had played soccer but not at the elite level, and people of the same age who did not play soccer. Here is a two-way table that classifies these individuals by whether or not they had arthritis of the hip or knee by their mid-50s.
$$\begin{array} {lc} & \text{Soccer experience} \ \text {Arthritis} &\begin{array}{l|c|c|c|c} & & & \text { Did not } & \\ & \text { Elite } & \text { Non-elite } & \text { play } & \text { Total } \\ \hline \text { Yes } & 10 & 9 & 24 & 43 \\ \hline \text { No } & 61 & 206 & 548 & 815 \\ \hline \text { Total } & 71 & 215 & 572 & 858 \end{array} \end{array}$$
Suppose we choose one of these players at random. What is the probability that the player has arthritis?

2021-08-08
We note that 10 players were elite players with arthritis, 9 players were non-elite players with arthritis and 24 players with arthritis did not play.
The probability is the number of favorable outcomes divided by the number of possible outcomes.
The probability of a player having arthritis is then the total number of players with arthritis divided by the sample size:
P(arthritis)=# of favorable outcomes/# of possible outcomes=(10+9+24)/(10+61+9+206+24+548)=48/858 ~ 0.0501=5.01%