where p, g, and rare the proportions of A, B, and O in the population.

Use the fact that

Kaycee Roche
2020-11-08
Answered

Three alleles (alternative versions of a gene) A, B, and O determine the four blood types A (AA or AO), B (BB or BO), O (OO), and AB. The Hardy-Weinberg Law states that the proportion of Boas in a population who carry two different alleles is

$P=2pq+2pr+2rq$

where p, g, and rare the proportions of A, B, and O in the population.

Use the fact that$p+q+r=1$ to show that P is at most

$\frac{2}{3}.$

where p, g, and rare the proportions of A, B, and O in the population.

Use the fact that

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Mean (change)

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