Question

Find the equation of a circle whose center is at (3, 3) and tangent to the circle x^2+ y^2 - 6x - 8y + 16 = 0. Draw the circles.

Circles
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asked 2021-08-08

Find the equation of a circle whose center is at (3, 3) and tangent to the circle \(x^2+ y^2 - 6x - 8y + 16 = 0\). Draw the circles.
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Answers (1)

2021-08-09

Explanation:
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