Question

Identify and graph the conic whose equation is in attachment.5x^2+4xy+2y^2-frac{28}{\sqrt5}x-\frac{4}{\sqrt5}y+4=0

Conic sections
ANSWERED
asked 2021-08-14

Identify and graph the conic whose equation is in attachment.
\(\displaystyle{5}{x}^{{2}}+{4}{x}{y}+{2}{y}^{{2}}-{\frac{{{28}}}{{\sqrt{{5}}}}}{x}-{\frac{{{4}}}{{\sqrt{{5}}}}}{y}+{4}={0}\)
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Expert Answers (1)

2021-08-15

I hope my answer below will help you
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