If AB=6 and AC=8, which statement will justify similarity by SAS?

1) DE=9, DF=12, and

2) DE=8, DF=10, and

3) DE=36, DF=64, and

4) DE=15, DF=20, and

ddaeeric
2021-07-30
Answered

In the diagram, $\mathrm{\u25b3}ABC\sim \mathrm{\u25b3}DEF$ .

If AB=6 and AC=8, which statement will justify similarity by SAS?

1) DE=9, DF=12, and$\mathrm{\angle}A\stackrel{\sim}{=}\mathrm{\angle}D$

2) DE=8, DF=10, and$\mathrm{\angle}A\stackrel{\sim}{=}\mathrm{\angle}D$

3) DE=36, DF=64, and$\mathrm{\angle}C\stackrel{\sim}{=}\mathrm{\angle}F$

4) DE=15, DF=20, and$\mathrm{\angle}C\stackrel{\sim}{=}\mathrm{\angle}F$

If AB=6 and AC=8, which statement will justify similarity by SAS?

1) DE=9, DF=12, and

2) DE=8, DF=10, and

3) DE=36, DF=64, and

4) DE=15, DF=20, and

You can still ask an expert for help

Adnaan Franks

Answered 2021-07-31
Author has **92** answers

Step 1

Given Data:

The length of side AB is: AB=6

The length of side AC is: AC=8

According to SAS, two pairs of corresponding sides of both triangles should be in the same proportion, and the angle made by these two adjacent lines of each triangle is congruent then they call similar triangle by SAS similarity.

From SAS similarity rule,

Condition 1:$\frac{AB}{DE}=\frac{AC}{DF}$

Condition 2:$\mathrm{\angle}A\stackrel{\sim}{=}\mathrm{\angle}D$

Step 2

For option (1), DE=9, DF=12,$\mathrm{\angle}A\stackrel{\sim}{=}\mathrm{\angle}D$

Substitute all the values in condition 1,

$\frac{6}{9}=\frac{8}{12}$

0.67=0.67

Option (1) satisfies condition 2 too.

So, option (1) satisfies each condition.

For option (2), DE=8, DF=10,$\mathrm{\angle}A\stackrel{\sim}{=}\mathrm{\angle}D$

Substitute all the values in condition 1,

$\frac{6}{8}=\frac{8}{10}$

$0.75\ne q0.8$

So, option (2) satisfies only condition 2.

Step 3

For option (3), DE=36, DF=64,$\mathrm{\angle}C\stackrel{\sim}{=}\mathrm{\angle}F$

Substitute all the values in condition 1,

$\frac{6}{36}=\frac{8}{64}$

$0.17\ne q0.125$

Option (3) does not satisfy condition 2.

For option (4), DE=15, DF=20,$\mathrm{\angle}C\stackrel{\sim}{=}\mathrm{\angle}F$

Substitute all the values in condition 1,

$\frac{6}{15}=\frac{8}{20}$

0.4=0.4

Option (4) does not satisfy condition 2.

Thus, option (1) is the correct option.

Given Data:

The length of side AB is: AB=6

The length of side AC is: AC=8

According to SAS, two pairs of corresponding sides of both triangles should be in the same proportion, and the angle made by these two adjacent lines of each triangle is congruent then they call similar triangle by SAS similarity.

From SAS similarity rule,

Condition 1:

Condition 2:

Step 2

For option (1), DE=9, DF=12,

Substitute all the values in condition 1,

0.67=0.67

Option (1) satisfies condition 2 too.

So, option (1) satisfies each condition.

For option (2), DE=8, DF=10,

Substitute all the values in condition 1,

So, option (2) satisfies only condition 2.

Step 3

For option (3), DE=36, DF=64,

Substitute all the values in condition 1,

Option (3) does not satisfy condition 2.

For option (4), DE=15, DF=20,

Substitute all the values in condition 1,

0.4=0.4

Option (4) does not satisfy condition 2.

Thus, option (1) is the correct option.

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