Find the rates of the two bikers if Bug goes mph faster the Ed on motorcycle and Bug travels 105 mi distance

aortiH

aortiH

Answered question

2021-08-02

The rates of the two bikers if Bug goes mph faster the Ed on motorcycle and Bug travels 105 mi distance in same amount of time in which Ed travels 90 mi.

Answer & Explanation

Corben Pittman

Corben Pittman

Skilled2021-08-03Added 83 answers

Hence, Bug speed will be:
x+10
Consider the provided proportion will be as:
90x=105x+10
An equation that equates two rates or ratios is called proportions:
ab=cd
Where (b0, d0)
To ssolve the proportions multiply both sides of the equation by LCD.
Hence the LCD of the provided proportion is x(x+10)
Hence, multiply both sides of the equation by x(x+10) as:
x(x+10)90x=105x+10(x(x+10))
Further simplify as:
x(x+10)90x=105x+10(x(x+10))
90(x+10)=105x
90x+900=105x
Subtract 90x from both sides of the equation as:
90x+90090x=105x90x
900=15x
Now divide both sides of the equation by 15 as:
900=15x
90015=15x15
x=60
Bud speed is:
x+10=60+10
=70
Hence, Ed travels 60 mph and whereas Bud travel 70mph.

Jeffrey Jordon

Jeffrey Jordon

Expert2021-12-17Added 2605 answers

Answer is given below (on video)

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