An equation that equates two rates or ratios is called proportions.

\(\displaystyle{\frac{{{a}}}{{{b}}}}={\frac{{{c}}}{{{d}}}}\)

Where \(\displaystyle{\left({b}\ne{q}{0},\ {d}\ne{q}{0}\right)}\)

To solve the proportions multiply both sides of the equation by LCD.

Calculation:

A bag of popcorn constains 4 gram of fat per serving if a serving is \(\displaystyle{2}-{o}{z}\)

Let x be the number of grams of fat in \(\displaystyle{5}-{o}{z}\)

Consider the provided proportion will be as:

\(\displaystyle{\frac{{{4}{g}}}{{{2}{o}{z}}}}={\frac{{{x}{g}}}{{{5}{o}{z}}}}\)

An equation that equates two rates or ratios is called proportions.

\(\displaystyle{\frac{{{a}}}{{{b}}}}={\frac{{{c}}}{{{d}}}}\)

Where \(\displaystyle{\left({b}\ne{q}_{0}\right)},\ {d}\ne{q}_{0}{)}\)

To solve the proportions, multiply both sides of the equation by LDC.

Hence the LCD of the provided proportion is \(\displaystyle{10}{o}{z}\)

Hence, multiply both sides of the equation by \(\displaystyle{10}{o}{z}\) as:

\(\displaystyle{\left({10}\right)}{\frac{{{4}{g}}}{{{2}{o}{z}}}}={\frac{{{x}}}{{{5}{o}{z}}}}{\left({10}\right)}\)

Further simplify as:

\(\displaystyle{\left({10}\right)}{\frac{{{4}{g}}}{{{2}{o}{z}}}}={\frac{{{x}{g}}}{{{5}{o}{z}}}}{\left({10}\right)}\)

\(\displaystyle{5}{\left({4}\right)}={2}{x}\)

\(\displaystyle{20}={2}{x}\)

Now divide both sides of the equation by 2 as:

\(\displaystyle{20}={2}{x}\)

\(\displaystyle{\frac{{{20}}}{{{2}}}}={\frac{{{2}{x}}}{{{2}}}}\)

\(\displaystyle{x}={10}\)

Hence, the amount of fat in \(\displaystyle{5}-{o}{z}\) bag is 10 gram.