Question

# How many drams of fat is there in 5-oz bag.

Ratios, rates, proportions
How many drams of fat is there in $$\displaystyle{5}-{o}{z}$$ bag.

2021-08-07

An equation that equates two rates or ratios is called proportions.
$$\displaystyle{\frac{{{a}}}{{{b}}}}={\frac{{{c}}}{{{d}}}}$$
Where $$\displaystyle{\left({b}\ne{q}{0},\ {d}\ne{q}{0}\right)}$$
To solve the proportions multiply both sides of the equation by LCD.
Calculation:
A bag of popcorn constains 4 gram of fat per serving if a serving is $$\displaystyle{2}-{o}{z}$$
Let x be the number of grams of fat in $$\displaystyle{5}-{o}{z}$$
Consider the provided proportion will be as:
$$\displaystyle{\frac{{{4}{g}}}{{{2}{o}{z}}}}={\frac{{{x}{g}}}{{{5}{o}{z}}}}$$
An equation that equates two rates or ratios is called proportions.
$$\displaystyle{\frac{{{a}}}{{{b}}}}={\frac{{{c}}}{{{d}}}}$$
Where $$\displaystyle{\left({b}\ne{q}_{0}\right)},\ {d}\ne{q}_{0}{)}$$
To solve the proportions, multiply both sides of the equation by LDC.
Hence the LCD of the provided proportion is $$\displaystyle{10}{o}{z}$$
Hence, multiply both sides of the equation by $$\displaystyle{10}{o}{z}$$ as:
$$\displaystyle{\left({10}\right)}{\frac{{{4}{g}}}{{{2}{o}{z}}}}={\frac{{{x}}}{{{5}{o}{z}}}}{\left({10}\right)}$$
Further simplify as:
$$\displaystyle{\left({10}\right)}{\frac{{{4}{g}}}{{{2}{o}{z}}}}={\frac{{{x}{g}}}{{{5}{o}{z}}}}{\left({10}\right)}$$
$$\displaystyle{5}{\left({4}\right)}={2}{x}$$
$$\displaystyle{20}={2}{x}$$
Now divide both sides of the equation by 2 as:
$$\displaystyle{20}={2}{x}$$
$$\displaystyle{\frac{{{20}}}{{{2}}}}={\frac{{{2}{x}}}{{{2}}}}$$
$$\displaystyle{x}={10}$$
Hence, the amount of fat in $$\displaystyle{5}-{o}{z}$$ bag is 10 gram.