Given P(x)=3x^{5}-x^{4}+81x^{3}-27x^{2}-972x+324, and that 6i is a zero, write P in factored form (as a product of linear factors). Be sure to write the full equation, including P(x)=.

Suman Cole 2021-08-02 Answered
Given \(\displaystyle{P}{\left({x}\right)}={3}{x}^{{{5}}}-{x}^{{{4}}}+{81}{x}^{{{3}}}-{27}{x}^{{{2}}}-{972}{x}+{324}\), and that 6i is a zero, write P in factored form (as a product of linear factors). Be sure to write the full equation, including \(\displaystyle{P}{\left({x}\right)}=\).

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Expert Answer

Liyana Mansell
Answered 2021-08-03 Author has 16630 answers
Step 1
\(\displaystyle{P}{\left({x}\right)}={3}{x}^{{{5}}}-{x}^{{{4}}}+{81}{x}^{{{3}}}-{27}{x}^{{{2}}}-{972}{x}+{324}\)
Given: 6i is a zero.
\(\displaystyle\Rightarrow-{6}{i}\) is also a zero.
\(\displaystyle\Rightarrow{\left({x}+{6}{i}\right)}{\left({x}-{6}{i}\right)}\) in a factor
\(\displaystyle\Rightarrow{\left({x}^{{{2}}}+{36}\right)}\) in a factor of P(x).
Step 2
\(\displaystyle{P}{\left({x}\right)}={3}{x}^{{{5}}}-{x}^{{{4}}}+{81}{x}^{{{3}}}-{27}{x}^{{{2}}}-{972}{x}+{324}\)
\(\displaystyle={x}^{{{4}}}{\left({3}{x}-{1}\right)}+{27}{x}^{{{2}}}{\left({3}{x}-{1}\right)}-{324}{\left({3}{x}-{1}\right)}\)
\(\displaystyle={\left({3}{x}-{1}\right)}{\left({x}^{{{4}}}+{27}{x}^{{{2}}}-{324}\right)}\)
\(\displaystyle={\left({3}{x}-{1}\right)}{\left[{x}^{{{2}}}{\left({x}^{{{2}}}+{36}\right)}-{9}{\left({x}^{{{2}}}+{36}\right)}\right]}\)
\(\displaystyle={\left({3}{x}-{1}\right)}{\left({x}^{{{2}}}+{36}\right)}{\left({x}^{{{2}}}-{9}\right)}\)
\(\displaystyle={\left({3}{x}-{1}\right)}{\left({x}^{{{2}}}+{36}\right)}{\left({x}+{3}\right)}{\left({x}-{3}\right)}\)
Factored form of P(x):
\(\displaystyle{P}{\left({x}\right)}={\left({3}{x}-{1}\right)}{\left({x}^{{{2}}}+{36}\right)}{\left({x}+{3}\right)}{\left({x}-{3}\right)}\)
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