# Solve the following equation with special factors. 27x^{4} - 3x^{2} = 0 The values of x are ____, ____, and ____.

Solve the following equation with special factors.
$27{x}^{4}-3{x}^{2}=0$
The values of x are ____, ____, and ____.
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Anonym
$27{x}^{4}-3{x}^{2}=0$
or $3{x}^{2}\left(9{x}^{2}-1\right)=0$
or ${x}^{2}\left(9{x}^{2}-1\right)=0$
or ${x}^{2}\left(3x+1\right)\left(3x-1\right)=0$
$\because {x}^{2}=0,3x+1=0,3x-1=0$
$\because x=0,x=-\frac{1}{3},x=\frac{1}{3}$
The values of x are $-\frac{1}{3},0,\frac{1}{3}$