# One of the wagers in roulette is to bet that the ball will stop on a number that a multiple of 3. If the ball stops on such a number, the player wins double the amount bet. What is the probability of winning this bet?

One of the wagers in roulette is to bet that the ball will stop on a number that a multiple of 3. (The roulette wheel Includes the numbers 0,00and 1 - 36 . and 00 are not considered multiples of 3.) If the ball stops on such a number, the player wins double the amount bet. What is the probability of winning this bet? (Write your answer as a fraction.)
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Step 1
It is given that in a roulette, if ball stops on a number, which is a multiple of 3, the player wins the bet.
Step 2
Total number of outcomes,

Favourable out comes,
$\left\{0,3,6,9,12,15,18,21,24,27,30,33,36\right\}⇒13$
Probability of winning $=\frac{\text{Favourable out comes}}{\text{Total outcomes}}$
$⇒\frac{13}{38}$
Hence probability of winning $=\frac{13}{38}$