One of the wagers in roulette is to bet that the ball will stop on a number that a multiple of 3. If the ball stops on such a number, the player wins double the amount bet. What is the probability of winning this bet?

Question

One of the wagers in roulette is to bet that the ball will stop on a number that a multiple of 3. If the ball stops on such a number, the player wins double the amount bet. What is the probability of winning this bet?

Expert Answer

yagombyeR

Answered 2021-08-11 Author has 14235 answers

Step 1
It is given that in a roulette, if ball stops on a number, which is a multiple of 3, the player wins the bet.
Step 2
Total number of outcomes,
$\left\{0,00\ and\ 1-36\right\} \Rightarrow 38$
Favourable out comes,
$\left\{0,3,6,9,12,15,18,21,24,27,30,33,36\right\} \Rightarrow 13$
Probability of winning $\displaystyle={\frac{{\text{Favourable out comes}}}{{\text{Total outcomes}}}}$
$\displaystyle\Rightarrow{\frac{{{13}}}{{{38}}}}$
Hence probability of winning $\displaystyle={\frac{{{13}}}{{{38}}}}$

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